Welcome to Westonci.ca, where finding answers to your questions is made simple by our community of experts. Discover precise answers to your questions from a wide range of experts on our user-friendly Q&A platform. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.
Sagot :
[tex]\sqrt{48n^9}=\sqrt{16n^8\cdot3n}=\sqrt{16n^8}\cdot\sqrt{3n}=4n^4\sqrt{3n}[/tex]
Answer:
[tex]4n^4\sqrt{3n}[/tex]
Step-by-step explanation:
Use the exponent rules:
[tex]\sqrt[n]{x^a} = x^{\frac{a}{n}}[/tex]
[tex]\sqrt[n]{a^n} =a[/tex]
To find the simplified form of :
[tex]\sqrt{48n^9}[/tex]
We can write 48 and [tex]n^9[/tex] as:
[tex]48 = 4 \cdot 4 \cdot 3 = 4^2 \cdot 3[/tex]
[tex]n^9 = (n^4)^2 \cdot n[/tex]
then;
[tex]\sqrt{4^2 \cdot 3 \cdot (n^4)^2 \cdot n}[/tex]
Apply the exponent rule:
⇒[tex]4 \cdot n^4 \cdot \sqrt{3n}[/tex]
⇒[tex]4n^4\sqrt{3n}[/tex]
Therefore, the simplified form of square root 48n^9 is, [tex]4n^4\sqrt{3n}[/tex]
Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.
