Westonci.ca is the best place to get answers to your questions, provided by a community of experienced and knowledgeable experts. Connect with a community of experts ready to help you find solutions to your questions quickly and accurately. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.
Sagot :
[tex]\sqrt{48n^9}=\sqrt{16n^8\cdot3n}=\sqrt{16n^8}\cdot\sqrt{3n}=4n^4\sqrt{3n}[/tex]
Answer:
[tex]4n^4\sqrt{3n}[/tex]
Step-by-step explanation:
Use the exponent rules:
[tex]\sqrt[n]{x^a} = x^{\frac{a}{n}}[/tex]
[tex]\sqrt[n]{a^n} =a[/tex]
To find the simplified form of :
[tex]\sqrt{48n^9}[/tex]
We can write 48 and [tex]n^9[/tex] as:
[tex]48 = 4 \cdot 4 \cdot 3 = 4^2 \cdot 3[/tex]
[tex]n^9 = (n^4)^2 \cdot n[/tex]
then;
[tex]\sqrt{4^2 \cdot 3 \cdot (n^4)^2 \cdot n}[/tex]
Apply the exponent rule:
⇒[tex]4 \cdot n^4 \cdot \sqrt{3n}[/tex]
⇒[tex]4n^4\sqrt{3n}[/tex]
Therefore, the simplified form of square root 48n^9 is, [tex]4n^4\sqrt{3n}[/tex]
Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.
