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What volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia? N2 + 3H2 --> 2NH3

Sagot :

Volume of hydrogen required to produce ammonia = 3*5 = 15L
since, 1 mole of nitrogen reacts with 3 moles of hydrogen to produce ammonia.
Amount of ammonia produced = 2*5 = 10L as 1 mole of nitrogen produces 2 moles of ammonia
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