kobiquinn11
Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Experience the ease of finding quick and accurate answers to your questions from professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

how do you solve 2x^2-32=0 using square roots? 

Please help!

Sagot :

Lilith
[tex]2x^2-32=0 \ \ / :2 \\ \\ x^2-16=0 \\ \\x^2-4^2 = 0 \\ \\ (x-4)(x+4)=0 \\ \\ x-4 = 0 \ \ or \ \ x+4 = 0\\ \\ x=4\ \ or \ \ x=-4[/tex]


kate200468
[tex]2x^2-32=0\\\\2(x^2-16)=0\ /:x^2-16=0\\\\x^2-4^2=0\\\\(x-4)(x+4)=0\\\\x-4=0\ \ \ \ or\ \ \ \ \ x+4=0\\\\x=4\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ x=-4[/tex]
We hope our answers were useful. Return anytime for more information and answers to any other questions you have. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.