Welcome to Westonci.ca, where you can find answers to all your questions from a community of experienced professionals. Connect with professionals on our platform to receive accurate answers to your questions quickly and efficiently. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
x2+2x-8 =0
x2 + 4x - 2x - 8 = 0
x(x+4) - 2(x+4) = 0
(x-2)(x+4) = 0
let x- 2 = 0
x = 2
let x+4 = 0
x= -4
x2 + 4x - 2x - 8 = 0
x(x+4) - 2(x+4) = 0
(x-2)(x+4) = 0
let x- 2 = 0
x = 2
let x+4 = 0
x= -4
[tex] x^{2} +2x=8 \ add \ 1 \ to \ both \ sides\\
\\
x^{2} +x+8+1 \ in \ the \ left \ side \ you \ find \ a perfect \ square \ trinomial\\
\\
(x+1)^2=9\\
\\
So:\\
\\
x+1=\pm \sqrt{9}\\
\\
x+1=\pm 3\\
\\
x+1=3 \rightarrow x=2\\
\\
x+1=-3 \rightarrow \x=-4[/tex]
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.