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find the lateral area and surface area of a right cone with radius 6 in. and height 8 in. give your answers in terms of pie

Sagot :

[tex]r=6in\\\\H=8in\\\\A=\pi rl\\\\Pythagoras\ theorem:\\\\r^2+H^2=l^2\\\\l^2=6^2+8^2\\\\l^2=36+64\\\\l^2=100\\\\l=\sqrt{100}\\\\l=10\ (in)[/tex]

[tex]A=\pi\cdot6\cdot10=60\pi\ (in^2)[/tex]
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