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Sagot :
The density of water is very close to 1.0 gm/ml.
The object is more dense than water.
It will sink in water.
The object is more dense than water.
It will sink in water.
The object will sink, because it is more dense than water.
Let's see this in detail. There are two forces acting on the object:
- its weight, which points downward, given by
[tex] W=mg=\rho_o V_o g [/tex]
where [tex] \rho_o [/tex] is the object's density, [tex] V_o [/tex] is its volume, and g is the gravitational acceleration.
- The buoyancy force, which points upward, given by
[tex] B=\rho_w V_w g [/tex]
where [tex] \rho_w [/tex] is the water density, [tex] V_w [/tex] is the volume of water displaced by the object.
We see that it is always [tex] W>B [/tex], so the object will sink. In fact:
[tex] \rho_o > \rho_w [/tex]. We are told the object's density is 1.05 g/mL, while the water density is 1.00 g/mL.
[tex] V_o \geq V_w [/tex]: the two volumes are equal when the object is completely submersed, and the volume of water displaced cannot be greater than the volume of the object.
So, W > B, and the object will sink.
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