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how do I solve x=y+8
and 5x+3y=12in substitution form

Sagot :

crisforp
5*(y + 8) + 3*y = 12 <=> 8*y + 40 = 12 ,<=> 8*y = -28 < => y = -7/2;

x = y + 8 => x = -7/2 + 8 => x = 9/2.
poppytartzspam

Answer:

x = 4.5 and y = -3.5

Step-by-step explanation:

To find the solution to this system of equations using the substitution method, you must solve for either the x or y variable and then substitute into the other equation.

x = (y + 8)

5x + 3y = 12

We will use the first equation to solve for x. The x has to be isolated on one side. Since the first equation already has x on the one side, we can plug it into the other equation.

5(y+8) + 3y = 12

Distribute and solve:

5y + 40 + 3y = 12

8y + 40 = 12

8y = 12-40

8y = -28

y = -3.5

Now we have the y variable, we can plug that back into the first equation to find x.

x = (-3.5) + 8

x= 4.5

Your answer will be x = 4.5 and y = -3.5

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