Answered

At Westonci.ca, we provide reliable answers to your questions from a community of experts. Start exploring today! Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

if the equation is h= -2x^2 + 12x -10

how do I find the max height?

Sagot :

D3xt3R
One other way to solve this question is finding the derivative

[tex]h=-2x^2+12x-10[/tex]

[tex]h'=-4x+12[/tex]

now we have to find when this function will be zero

[tex]-4x+12=0[/tex]

[tex]\boxed{\boxed{x=3}}[/tex]

now we just replace this value at our initial function

[tex]h=-2x^2+12x-10[/tex]

[tex]h_{max}=-2*(3)^2+12*3-10[/tex]

[tex]h_{max}=-18+36-10[/tex]

[tex]\boxed{\boxed{h_{max}=8}}[/tex]
Ryan2
The maximum height is the ordinate value of the vertex of the parabola, ie: yV

Calculating yV:

[tex]y_V=\frac{-\Delta}{4a}\\ \\ y_V=-[\frac{12^2-4*(-2)*(-10)]}{4*(-2)}=\frac{-(144-80)}{-8}=\frac{-64}{-8}=8[/tex]
We appreciate your time. Please revisit us for more reliable answers to any questions you may have. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Westonci.ca is committed to providing accurate answers. Come back soon for more trustworthy information.