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dx+hy=j   what does x=

Sagot :

Ryan2
[tex]dx+hy=j\\ \\ dx=j-hy\\ \\ \boxed{x=\frac{j-hy}{d}}[/tex]
kate200468
[tex]dx+hy=j\\\\dx=j-hy\ /:d\ \ \ \ and\ \ \ \ d \neq 0\\\\x= \frac{j-hy}{d} [/tex]
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