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Sagot :
[tex]radius : \ r= 5 \ in \\ height : \ h = 18 \ in \\ \\Volume \ of \Cone : \\ \\ V= = \frac{1} { 3 } \pi \cdot r^2 \cdot h\\ \\V=\frac{1}{\not3^1}\cdot \pi \cdot 5^2 \cdot \not18^6= 6\cdot 25 \cdot \pi= 150 \ \pi \ in^3 \\ \\Answer: \ A. \ \ 150 \ \pi \ in^3[/tex]
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