Answered

Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Our Q&A platform provides quick and trustworthy answers to your questions from experienced professionals in different areas of expertise. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.


A passenger train's speed is 60 mi/h, and a freight train's speed is 40 mi/h. The passenger train travels the same distance in 1.5 h less time than the freight train. How long does each train take to make the trip?

Sagot :

AL2006
Wow !  Let's see now . . .

Let's say the passenger train takes ' P ' hours for the trip.
Then the freight train takes ' P + 1.5 ' hours for the same distance.

The speed of the passenger train is 60, so he covers ' 60P ' miles.
The speed of the freight train is 40, to he covers ' 40(p+1.5) ' miles.
But the distances are equal !

60P = 40(P + 1.5) . . . . . There's your equation !

Eliminate parentheses on the right side:

60P = 40P + 60

Subtract 40P from each side:

20P = 60

Divide each side by 20 :

P = 3

The passenger train takes 3 hours, and the
freight train takes (P+1.5) = 4.5 hours.

Check:

In 3 hours, the passenger train covers (3 x 60) = 180 miles .
In 4.5 hours, the freight train covers (4.5 x 40) = 180 miles .
It works.
yay !


Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.