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Sagot :
Wow ! Let's see now . . .
Let's say the passenger train takes ' P ' hours for the trip.
Then the freight train takes ' P + 1.5 ' hours for the same distance.
The speed of the passenger train is 60, so he covers ' 60P ' miles.
The speed of the freight train is 40, to he covers ' 40(p+1.5) ' miles.
But the distances are equal !
60P = 40(P + 1.5) . . . . . There's your equation !
Eliminate parentheses on the right side:
60P = 40P + 60
Subtract 40P from each side:
20P = 60
Divide each side by 20 :
P = 3
The passenger train takes 3 hours, and the
freight train takes (P+1.5) = 4.5 hours.
Check:
In 3 hours, the passenger train covers (3 x 60) = 180 miles .
In 4.5 hours, the freight train covers (4.5 x 40) = 180 miles .
It works.
yay !
Let's say the passenger train takes ' P ' hours for the trip.
Then the freight train takes ' P + 1.5 ' hours for the same distance.
The speed of the passenger train is 60, so he covers ' 60P ' miles.
The speed of the freight train is 40, to he covers ' 40(p+1.5) ' miles.
But the distances are equal !
60P = 40(P + 1.5) . . . . . There's your equation !
Eliminate parentheses on the right side:
60P = 40P + 60
Subtract 40P from each side:
20P = 60
Divide each side by 20 :
P = 3
The passenger train takes 3 hours, and the
freight train takes (P+1.5) = 4.5 hours.
Check:
In 3 hours, the passenger train covers (3 x 60) = 180 miles .
In 4.5 hours, the freight train covers (4.5 x 40) = 180 miles .
It works.
yay !
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