Answered

Westonci.ca is the premier destination for reliable answers to your questions, brought to you by a community of experts. Connect with a community of experts ready to provide precise solutions to your questions on our user-friendly Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

Use Pascal's triangle or the Binomial theorem to expand the binomials.
1. (3c-2d)^4
2. (2n+3)^5
3. (x^2+4)^3

Sagot :

[tex](3c-2d)^4=(3c)^4-4(3c)^3\cdot2d+6\cdot(3c)^2\cdot(2d)^2-4\cdot3c\cdot(2d)^3-(2d)^4\\\\=81c^4-216c^3d+216c^2d^2-96cd^3-16d^4\\-------------------------------\\(2n+3)^2\\=(2n)^5+5(2n)^4\cdot3+10(2n)^3\cdot3^2+10(2n)^2\cdot3^3+5\cdot2n\cdot3^4+3^5\\\\=32n^5+240n^4+720n^3+1080n^2+810n+243\\-------------------------------\\(x^2+4)^3=(x^2)^3+3(x^2)^2\cdot4+3x^2\cdot4^2+4^3\\\\=x^6+12x^4+48x^2+64[/tex]
View image Аноним
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.