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Sagot :
[tex](2y+3x)^2=9\iff2y+3x=3\ \vee\ 2y+3x=-3\\\\2y=-3x+3\ \vee\ 2y=-3x-3\\\\y=-\frac{3}{2}x+\frac{3}{2}\ \vee\ y=-\frac{3}{2}x-\frac{3}{2}[/tex]
[tex](2y+3x)^2=9 \\
\\
\sqrt{(2y+3x)^2}=\sqrt9\\
\\
2y+3x=3\\
\\
2y=3-3x\\
\\
\boxed{y=\frac{3-3x}{2} }[/tex]
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