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A bag contains 2 red, 4 yellow, and 6 blue marbles.Two marbles are drawn at random. Find the portability that both are blue.

Sagot :

mackiemesser
Total number of marbles is 12, there are 6 blues.
When picking the first one the probability to pick the right one is [tex]\frac{6}{12}=\frac{1}{2}[/tex]
When we pick the second one there are 11 marbles and only 5 blue so the probabilty is [tex]\frac{5}{11}[/tex]

We need to pick 2 blues one after another so we multiply probabilities [tex]\frac{1}{2}*\frac{5}{11}=5/22=0.227[/tex] The probability is around 23%
abidemiokin

If two marbles are drawn at random, the probability that they are both blue is 1/4

The formula for calculating the probability is given as:

Probability = Expected outcome/Total outcome

  • Given that a bag contains 2 red, 4 yellow, and 6 blue marbles

  • Total outcome = 2 + 4 + 6 = 12 marbles

Since we are to find a probability of picking 2 blue balls

Pr(2 blue balls) = 6/12 * 6/12

Pr(2 blue balls) = 1/2 * 1/2

Pr(2 blue balls) = 1/4

Hence if two marbles are drawn at random, the probability that they are both blue is 1/4

Learn more here: https://brainly.com/question/22664861

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