Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Join our Q&A platform and connect with professionals ready to provide precise answers to your questions in various areas. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

What is the diagonal of a rectangle with length 48 inches and width 40 inches?

Sagot :

i think its D=w2+l2=402+482≈ 62.482in
iloveonedirection
Use the Pythagorean Theorem: [tex]a^2 + b^2 = c^2[/tex]
You can do this because when you cut the rectangle in half with the diagonal, it forms a right triangle, making the diagonal the hypotenuse (c). 

[tex]40^2 + 48^2 = c^2[/tex]

[tex]1600 + 2304 = c^2[/tex]

[tex]3904 = c^2[/tex]

[tex] \sqrt{3904} = \sqrt{c^2} [/tex]

[tex]62.48 = c[/tex]

Diagonal: 62.48 inches
View image iloveonedirection
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.