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What is the molality of a solution in which 3.0 moles of NaCl is dissolved in 1.5 Kg of water?

Sagot :

pyromorphite
density H2O = 1g/cm³
1,5 kg H2O = 1500g = 1500cm³             (1dm³ = 1000cm³)

3moles of NaCl-----in---------1500cm³ H2O
x moles of NaCl ----in--------1000cm³ H2O
x = 2moles of NaCl

answer: 2 mol/dm³

The molality of the sodium chloride solution is 2.0 mol/kg.

Given:

3.0 moles of NaCl in 1.5 kilograms of water.

To find:

The molality of the solution

Solution:

The moles of solute that is sodium chloride = 3.0 mol

The mass of solvent that is water = 1.5 kg

The molality of the solution:

[tex]=\frac{3.0 mol}{1.5 kg}=2.0 mol/kg[/tex]

The molality of the sodium chloride solution is 2.0 mol/kg.

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