Answered

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If p is a positive integer, which could be an odd integer?
(A) 2p + 2
(B) p^3 - p
(C) p^2 + p
(D) p^2 - p
(E) 7p - 3

Sagot :

turk3005
[tex]p > 0 \Rightarrow[/tex]

[tex]2p+2[/tex] (even)

[tex]p^3-p[/tex] (odd or even)

[tex]p^2 + p[/tex] (even)

[tex]p^2 - p[/tex] (even)

[tex]7p - 3[/tex] (ODD); 7p odd, 7p-3 = (odd)-(odd)=(odd)
kate200468
[tex]p>0\\\\(A)\ \ \ 2p+2=2(p+1)\ \rightarrow\ \ even\ number\\\\(B)\ \ \ p^3-p=p(p^2-1)=p(p-1)(p+1)\ \rightarrow\ \ even\ number\\\\(C)\ \ \ p^2+p=p(p+1)\ \rightarrow\ \ even\ number\\\\(D)\ \ \ p^2-p=p(p-1)\ \rightarrow\ \ even\ number\\\\(E)\ \ \ 7p-3=6p-4+p+1=2(3p-2)+p+1\\\\p-odd\ \rightarrow\ \ (p+1)- even\ \rightarrow\ (7p-3)-even\ number\\\\p-even\ \rightarrow\ \ (p+1)- odd\ \rightarrow\ (7p-3)-odd\ number\\\\Ans.\ E[/tex]
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