Answered

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Whats the equation of a circle centered at (7,1) that passes through (-2,10)

Sagot :

AL2006
The line from (7, 1) to (-2 10) is a radius of the circle.

Its length is the square root of [ (-2 - 7)² + (10 - 1)² ] =  √(81 + 81) = √162

The equation of the circle is: (x- 7)² + (y - 1)² = 162 
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