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Sagot :
The smaller number is 'x' .
The larger number is (x+ 20)
Their sum is [ x + (x + 20 ]
2x + 20 = 44
Subtract 20 from each side:
2x = 24
Divide each side by 2 :
x = 12
and
x + 20 = 32
The larger number is (x+ 20)
Their sum is [ x + (x + 20 ]
2x + 20 = 44
Subtract 20 from each side:
2x = 24
Divide each side by 2 :
x = 12
and
x + 20 = 32
Let the numebrs be x and y.
x + y = 44
x = y + 20
Substituting the value of x,
(y + 20) + y = 44
2y + 20 = 44
2y = 24
y = 12.
x = y + 20
x = 12+ 20
Thus, x = 32.
Thus, the two numbers are 32 and 12.
x + y = 44
x = y + 20
Substituting the value of x,
(y + 20) + y = 44
2y + 20 = 44
2y = 24
y = 12.
x = y + 20
x = 12+ 20
Thus, x = 32.
Thus, the two numbers are 32 and 12.
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