Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Get quick and reliable solutions to your questions from a community of seasoned experts on our user-friendly platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
The smaller number is 'x' .
The larger number is (x+ 20)
Their sum is [ x + (x + 20 ]
2x + 20 = 44
Subtract 20 from each side:
2x = 24
Divide each side by 2 :
x = 12
and
x + 20 = 32
The larger number is (x+ 20)
Their sum is [ x + (x + 20 ]
2x + 20 = 44
Subtract 20 from each side:
2x = 24
Divide each side by 2 :
x = 12
and
x + 20 = 32
Let the numebrs be x and y.
x + y = 44
x = y + 20
Substituting the value of x,
(y + 20) + y = 44
2y + 20 = 44
2y = 24
y = 12.
x = y + 20
x = 12+ 20
Thus, x = 32.
Thus, the two numbers are 32 and 12.
x + y = 44
x = y + 20
Substituting the value of x,
(y + 20) + y = 44
2y + 20 = 44
2y = 24
y = 12.
x = y + 20
x = 12+ 20
Thus, x = 32.
Thus, the two numbers are 32 and 12.
Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. We're glad you visited Westonci.ca. Return anytime for updated answers from our knowledgeable team.