Discover answers to your most pressing questions at Westonci.ca, the ultimate Q&A platform that connects you with expert solutions. Join our platform to connect with experts ready to provide accurate answers to your questions in various fields. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
Well, there are two cases in here:
1. The cylinder is at least the same height as its base diameter. The sphere will have the same diameter, which is 2r.
2. The cylinder is short, the height is strictly less than the base diameter. We will denote [tex]r=\frac{h}{2}[/tex].
The volume is [tex]\frac{4}{3} \pi r^{3}[/tex]
1. The cylinder is at least the same height as its base diameter. The sphere will have the same diameter, which is 2r.
2. The cylinder is short, the height is strictly less than the base diameter. We will denote [tex]r=\frac{h}{2}[/tex].
The volume is [tex]\frac{4}{3} \pi r^{3}[/tex]
Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.
