Westonci.ca makes finding answers easy, with a community of experts ready to provide you with the information you seek. Discover solutions to your questions from experienced professionals across multiple fields on our comprehensive Q&A platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
Well, there are two cases in here:
1. The cylinder is at least the same height as its base diameter. The sphere will have the same diameter, which is 2r.
2. The cylinder is short, the height is strictly less than the base diameter. We will denote [tex]r=\frac{h}{2}[/tex].
The volume is [tex]\frac{4}{3} \pi r^{3}[/tex]
1. The cylinder is at least the same height as its base diameter. The sphere will have the same diameter, which is 2r.
2. The cylinder is short, the height is strictly less than the base diameter. We will denote [tex]r=\frac{h}{2}[/tex].
The volume is [tex]\frac{4}{3} \pi r^{3}[/tex]
We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.
