Answered

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True or false. If a line L1has equation y = mx + b, where m and b are constants with m ≠ 0, then an equation of a line L2 perpendicular to L1 has the form y = -1/m x  C, where C is a constant.

Sagot :

[tex]L_1:y=mx+b\\\\L_2:y=-\frac{1}{m}\ \times\ C\\\\L_1\ \perp\ L_2-FALSE\\--------------------\\L_3\ \perp\ L_1\iff L_3=-\frac{1}{m}+C[/tex]
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