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Find the remainder when 2x^4-6x^3+2x^2-x+2 is divided by x+2

Sagot :

The answer to the problem would be 2x³-10x²+22x-45+92/(x+2)
So the remainder is 92.
kate200468
[tex] P(x)=2x^4-6x^3+2x^2-x+2 \ \ \ and\ \ \ x_0=-2\\\\the\ remainder:\\\\R(x)= 2(-2)^4-6(-2)^3+2(-2)^2-(-2)+2=\\\\=2\cdot16-6\cdot(-8)+2\cdot4+2+2=32+48+8+4=92[/tex]
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