shornoramiller3
Answered

At Westonci.ca, we make it easy for you to get the answers you need from a community of knowledgeable individuals. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

simplify as much as possible.
Assume that all variables represent positive real number
4x√32xv^2 + v√2x^3

Sagot :

[tex]4x\sqrt{32xv^2}+v\sqrt{2x^3}=4x\sqrt{16\cdot2}\cdot\sqrt{x}\cdot\sqrt{v^2}+v\sqrt2\cdot\sqrt{x^2\cdot x}\\\\=4x\cdot4\sqrt2\cdot\sqrt{x}\cdot v+v\sqrt2\cdot x\sqrt{x}=16xv\sqrt{2x}+xv\sqrt{2x}=17\sqrt{2x}\\\\========================================\\\\D;\\x\in < 0;\ \infty)\ \wedge\ v\in\mathbb{R}[/tex]
[tex]4x \sqrt{32xv^2}+v \sqrt{2x^3} = 4x \sqrt{16.2} . \sqrt{x} . \sqrt{v^2} + v \sqrt{2} . \sqrt{x^2} . x [/tex]
[tex]= 4x . \sqrt{2} . \sqrt{x} . v + v \sqrt{2} . x \sqrt{x} = 16 xv \sqrt{2x} + xv \sqrt{2x} [/tex] = [tex] 17\sqrt{2x} [/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.