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Solving systems by elimination:
2x + 4y = -4
3x + 5y = -3

Please show me your work so I can do the rest myself. Thanks!


Sagot :

[tex]2x+4y=-4 (/*3) [/tex]
[tex]3x+5y=-3 (/*(-2)) \Rightarrow [/tex]

[tex]6x+12y=-12[/tex]
[tex]-6x-10y=6 \Rightarrow[/tex]

[tex]2y=-6\Rightarrow y=-3[/tex]
[tex]y=-3\Rightarrow 2x+4y=-6\rightarrow 2x+4.(-3)=-6 \Rightarrow 2x-12=-6\Rightarrow[/tex]
[tex]2x=6\Rightarrow x=3[/tex]

[tex](x,y)=(3,-3)[/tex]

Answer:

222

Step-by-step explanation:

2x+4y=-4

3x+5y=-3------>  y=-3x-3

                                  5

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