Answered

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A 21 inch piece of steel is cut into three pieces so that the second piece is twice as long as the first, the third piece is 3 inches more than three times the length of the first piece. find the lengths of the pieces.

Sagot :

3f+3=t
s=2f
21=f+s+t                       

21=f+(2f)+(3f+3)
21=6f+3
18=6f

3=first
6=second
12=third


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