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Evaluate the function below for x=2.   F(x)=2x^3-x^2-5x+6

Sagot :

Ryan2
[tex]f(x)=2x^3-x^2-5x+6 \ \ \ \boxed{x=2}\\ \\ f(2)=2*2^3-2^2-5*2+6\\ \\ f(2)=16-4-10+6\\ \\ f(2)=8[/tex]

Answer:

A Function states an equation that has only one answer for y for every x. Also, a function assigns exactly one output to each input of a specified type.

i,e y= f(x) where x represents the input variable and y represents the output value.

Given the function: [tex]F(x) = 2x^3-x^2-5x+6[/tex]

Substitute the given input value of x =2 , we get;

[tex]F(2) = 2(2)^3-(2)^2-5(2)+6[/tex]

[tex]F(2) = 2(8)-4-10+6[/tex]

or

[tex]F(2) = 16-4-10+6[/tex]

Simplify:

[tex]F(2) = 8[/tex]

Therefore, the function [tex]F(x)=2x^3-x^2-5x+6[/tex] for x=2, we have F(2) =8.

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