Answered

At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

how do you describe the roots of 9y² - 6y + 5 = 0?

Sagot :

konrad509
[tex]9y^2- 6y + 5 = 0\\ 9y^2-6y+1+4=0\\ (3y-1)^2+4=0\\ (3y-1)^2=-4\\ y\in \emptyset [/tex]
Lilith
[tex]9y^2 - 6y + 5 = 0 \\ \\a=9, \ b= -6 , \ c=5 \\ \\\Delta =b^2-4ac = (-6)^2 -4\cdot9\cdot 5 = 36 -180 = -144 \\ \\ If\ \Delta <0, \ then \ roots\ are \ imaginary \ (non-real)[/tex]


We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.