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I  4b - 3  I  + 2 = 8

need help


Sagot :

[tex]|4b - 3 | + 2 = 8\\ |4b-3|=6\\ 4b-3=6 \vee 4b-3=-6\\ 4b=9 \vee 4b=-3\\ b=\frac{9}{4} \vee b=-\frac{3}{4} [/tex]