Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Discover in-depth solutions to your questions from a wide range of experts on our user-friendly Q&A platform. Get quick and reliable solutions to your questions from a community of experienced experts on our platform.

Differentiate the following functions y=4x^3-2x^2+5x^-3.7-6

Sagot :

secretlyblu
to differentiate we know that the rule is KX^n= (K*n)X^(n-1) where "K" is some constant , "X" is some variable and "n" is your exponent. so just apply this rule to your function. the first part is 4x^3. to differentiate you follow the rule. (4*3)x^(3-1). you get 12x^2. keep following this rule to the very end even with that -3.7 exponent. dont let the negative or the decimal point trip you up. and take care to change any positive to negative and vice versa should you need to. any how you should get y'=12x²-4x-18.5x^(-4.7)

remember that the 6 is no longer there because the derivative of a constant is zero :)
AL2006
I don't think you copied it correctly, but I'll assume that you did.

y = 4x³ - 2x² + 5('x' to the -3.7 power) - 6

"y-prime" (the first derivative) =  12x² - 4x - 18.5('x' to the -4.7 power)
Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We hope you found this helpful. Feel free to come back anytime for more accurate answers and updated information. Westonci.ca is your trusted source for answers. Visit us again to find more information on diverse topics.