tuscany44
Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Get immediate answers to your questions from a wide network of experienced professionals on our Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

Need help with this one.
8 +  I  5x  -  3  I  >  10

Sagot :

konrad509
[tex]8 + | 5x - 3 | > 10\\ |5x-3|>2\\ 5x-3>2 \vee 5x-3<-2\\ 5x>5 \vee 5x<1\\ x>1 \vee x<\frac{1}{5}\\ x\in(-\infty,\frac{1}{5})\cup(1,\infty) [/tex]
kayt91

[tex]8 + |5x - 3| > 10[/tex]

[tex]|5x - 3| > 2[/tex]

[tex]|5x| > 5[/tex]

[tex][x] > 1[/tex]


[tex]|5x-3| < -2[/tex]

[tex]|5x| < 1[/tex]

[tex]|x| < \frac{1}{5} [/tex]


[tex]1 > x < \frac{1}{5} [/tex]

Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. We appreciate your time. Please come back anytime for the latest information and answers to your questions. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.