Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.
Sagot :
if this is drawn out then the distance and the 9 miles east and 12miles north make a right-angled triangle. We can then use pythagoras' theorem. a^2+b^2=c^2 so 9^2+12^2=hypoteneuse^2
so 81+144=h^2
h^2=225
h=15
so the distance is 15km
so 81+144=h^2
h^2=225
h=15
so the distance is 15km
If the Earth were a flat surface, then 9 miles east and 12 miles north would be
the basis of a right triangle, and the straight-line route would be the hypotenuse.
We could use the Pythagorean Theorem to find the straight-line distance.
A² + B² = C²
C² = (9)² + (12)²
C² = 81 + 144
C² = 225
C = √225 = 15 miles
That's Choice-'H'.
the basis of a right triangle, and the straight-line route would be the hypotenuse.
We could use the Pythagorean Theorem to find the straight-line distance.
A² + B² = C²
C² = (9)² + (12)²
C² = 81 + 144
C² = 225
C = √225 = 15 miles
That's Choice-'H'.
We appreciate your visit. Our platform is always here to offer accurate and reliable answers. Return anytime. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.