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Sagot :
Total amount of numbers in the set = 8 .
Total amount that are divisible by both 2 and 3 = 3 .
So the probability of picking one of them is 3/8 = 37.5 percent.
Total amount that are divisible by both 2 and 3 = 3 .
So the probability of picking one of them is 3/8 = 37.5 percent.
[tex]|\Omega|=8\\
|A|=3\\
P(A)=\frac{|A|}{|\Omega|}\\
P(A)=\frac{3}{8}[/tex]
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