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Solve and simplify: 2/3 x 3/5 x 5/10 x 6/8 =
A: 1/5
B: 1/2
C: 3/20
D: 1/4

Sagot :

[tex]\frac{2}{3}\cdot\frac{3}{5}\cdot\frac{5}{10}\cdot\frac{6}{8}=\frac{2}{\not3_1}\cdot\frac{\not3^1}{\not5_1}\cdot\frac{\not5^1}{10}\cdot\frac{6}{8}=\frac{\not2^1}{10}\cdot\frac{6}{\not8_4}=\frac{\not6^3}{10\cdot\not4_2}=\frac{3}{20}\\\\\\Answer:C[/tex]