Answered

Welcome to Westonci.ca, the place where your questions find answers from a community of knowledgeable experts. Explore our Q&A platform to find in-depth answers from a wide range of experts in different fields. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

How do I solve b^2-5b-24=0

Sagot :

konrad509
[tex]b^2-5b-24=0\\ b^2-8b+3b-24=0\\ b(b-8)+3(b-8)=0\\ (b+3)(b-8)=0\\ b=-3 \vee b=8[/tex]
Lilith
[tex]b^2-5b-24=0\\ \\a=1 , \ b=-5, \ c= -24 \\ \\ \Delta =b^2-4ac = (-5)^2 -4\cdot1\cdot (-24) = 25 +96 =121 \\ \\x_{1}=\frac{-b-\sqrt{\Delta} }{2a}=\frac{5-\sqrt{121}}{2 }=\frac{ 5-11}{2}=\frac{-6}{2}=-3[/tex]

[tex]x_{2}=\frac{-b+\sqrt{\Delta} }{2a}=\frac{5+\sqrt{121}}{2 }=\frac{ 5+11}{2}=\frac{16}{2}= 8\\ \\Answer: x=-3 \ \ \ or \ \ \ x=8[/tex]





Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.