Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Join our platform to connect with experts ready to provide precise answers to your questions in different areas.

How do I solve n^2-5n-14=0 by factoring

Sagot :

(N-7)(n+2)=0 as you'd get n^2-7n+2n-14 then just simplify. Then it would be n=-2 or 7
[tex]n^2-5n-14=0 \\ n^2-7n+2n-14=0\\ n(n-7)+2(n-7)=0\\ (n+2)(n-7)=0\\ n=-2 \vee n=7[/tex]