Answered

Get the answers you need at Westonci.ca, where our expert community is always ready to help with accurate information. Connect with professionals ready to provide precise answers to your questions on our comprehensive Q&A platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

A particular circle in the standard (x,y) coordinate
plane has an equation of (x − 5)^2 + y^2 = 38. What are
the radius of the circle, in coordinate units, and the
coordinates of the center of the circle?
radius center
F. 38 ( 5,0)
G. 19 ( 5,0)
H. 38 ( 5,0)
J. 38 (−5,0)
K. 19 (−5,0)

Sagot :

[tex]the\ center\ of\ the\ circle:(a;\ b)\\the\ radius:r\\\\then\ the\ circle:(x-a)^2+(y-b)^2=r^2\\\\=========================\\\\(x-5)^2+y^2=38\\\\(x-5)^2+(y-0)^2=(\sqrt{38})^2\\\\center:(5;\ 0)\\radius:\sqrt{38}[/tex]
Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thanks for using our service. We're always here to provide accurate and up-to-date answers to all your queries. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.