Welcome to Westonci.ca, the ultimate question and answer platform. Get expert answers to your questions quickly and accurately. Get immediate and reliable solutions to your questions from a knowledgeable community of professionals on our platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

use the functions f(x) = 3x – 4 and g(x) = x2 – 2 to answer the following questions. Complete the tables.


x f(x)–3–1 0 2 5

x g(x)–3–1 0 2 5

For what value of the what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) {–3, –1, 0, 2, 5} does f(x) = g(x)? Answer:
















consider the relation {(–4, 3), (–1, 0), (0, –2), (2, 1), (4, 3)}.
Graph the relation.
State the domain of the relation. State the range of the relation. Is the relation a function? How do you know? Answer:











2. graph the function f(x) = |x + 2|.


Answer:







consider the following expression.
Rewrite the expression so that the first denominator is in factored form. Determine the LCD. (Write it in factored form.) Rewrite the expression so that both fractions are written with the LCD. Subtract and simplify.

Answer:


Sagot :

[tex]1)\\f(x)=3x-4\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ f(x)\ |\ \ -13\ \ |\ \ -7\ \ |\ -4\ \ |\ \ \ 2\ \ \ |\ \ \ 11\ \ |\\\\f(-3)=3\cdot(-3)-4=-9-4=-13\\f(-1)=3\cdot(-1)-4=-3-4=-7\\f(0)=3\cdot0-4=0-4=-4\\f(2)=3\cdot2-4=6-4=2\\f(5)=3\cdot5-4=15-4=11[/tex]

[tex]g(x)=x^2-2\\|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\\=========================\\|\ g(x)\ |\ \ \ \ \ 7\ \ \ \ |\ \ -1\ \ \ |\ -2\ \ |\ \ \ 2\ \ |\ \ \ 23\ \ |\\\\g(-3)=(-3)^2-2=9-2=7\\g(-1)=(-1)^2-2=1-2=-1\\g(0)=0^2-2=0-2=-2\\g(2)=2^2-2=4-2=2\\g(5)=5^2-2=25-2=23\\\\f(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x=2,\ \ \ \ because\ \ \ \ f(2)=2\ \ \ and\ \ \ g(2)=2[/tex]

[tex]2)\\the\ relation:\ \{(-4, 3), (-1, 0), (0, -2), (2,1), (4, 3)\}.\\\\the\ domain:\ D=\{-4,-1,0,2,4\}\\the\ range:\ R=\{3,0,-2,1\}\\\\This\ relation\ is\ the\ function,\ because\ \ each\ number\\ of\ the\ domain\ D\ has\ exactly\ one\ value\ in\ the\ range\ R. [/tex]

[tex]3)\\f(x)=|x+2|\\\\|x+2|= \left \{ {\big{x+2\ \ \ \ \ if\ \ \ x \geq -2} \atop \big{-x-2\ \ \ if\ \ \ x<-2}} \right. [/tex]
View image kate200468

Answer:

-11 and 0 for EDGE2020

f(4)= -11

If g(x)=2, x= 0

Step-by-step explanation: