Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.
Sagot :
for resistance we have R=ρ l/a
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
Answer: [tex]0.266 ohm^{-1}[/tex]
Explanation: Specific conductance or conductivity is the conductance for unit volume of a solution.
[tex]\kappa=C\times \frac{l}{a}[/tex]
where,
[tex]\kappa[/tex] =Specific conductance or Conductivity=[tex]0.80ohm^{-1}cm^{-1}[/tex]
C = Conductance = ?
l = length= 9.0 cm
a = area = 3.0[tex]cm^2[/tex]
[tex]\frac{length}{area}[/tex]= cell constant =[tex]\frac{9.0cm}{3.0cm^2}=3cm^{-1}[/tex]
[tex]0.80ohm^{-1}cm^{-1}=C\times 3cm^{-1}[/tex]
[tex]C=0.266 ohm^{-1}[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.