At Westonci.ca, we connect you with the best answers from a community of experienced and knowledgeable individuals. Get quick and reliable solutions to your questions from knowledgeable professionals on our comprehensive Q&A platform. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform.
Sagot :
for resistance we have R=ρ l/a
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
Answer: [tex]0.266 ohm^{-1}[/tex]
Explanation: Specific conductance or conductivity is the conductance for unit volume of a solution.
[tex]\kappa=C\times \frac{l}{a}[/tex]
where,
[tex]\kappa[/tex] =Specific conductance or Conductivity=[tex]0.80ohm^{-1}cm^{-1}[/tex]
C = Conductance = ?
l = length= 9.0 cm
a = area = 3.0[tex]cm^2[/tex]
[tex]\frac{length}{area}[/tex]= cell constant =[tex]\frac{9.0cm}{3.0cm^2}=3cm^{-1}[/tex]
[tex]0.80ohm^{-1}cm^{-1}=C\times 3cm^{-1}[/tex]
[tex]C=0.266 ohm^{-1}[/tex]
Thank you for your visit. We are dedicated to helping you find the information you need, whenever you need it. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.