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Sagot :
for resistance we have R=ρ l/a
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
thus for conductance we have K=σ a/l
conductance,K=1/R
conductivity,σ =1/ρ
σ = .80 Ω-1 cm-1
l =9 cm
a = 3 cm²
K=.80 ×3/9
=0.26 Ω-1
Answer: [tex]0.266 ohm^{-1}[/tex]
Explanation: Specific conductance or conductivity is the conductance for unit volume of a solution.
[tex]\kappa=C\times \frac{l}{a}[/tex]
where,
[tex]\kappa[/tex] =Specific conductance or Conductivity=[tex]0.80ohm^{-1}cm^{-1}[/tex]
C = Conductance = ?
l = length= 9.0 cm
a = area = 3.0[tex]cm^2[/tex]
[tex]\frac{length}{area}[/tex]= cell constant =[tex]\frac{9.0cm}{3.0cm^2}=3cm^{-1}[/tex]
[tex]0.80ohm^{-1}cm^{-1}=C\times 3cm^{-1}[/tex]
[tex]C=0.266 ohm^{-1}[/tex]
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