Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Get precise and detailed answers to your questions from a knowledgeable community of experts on our Q&A platform. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.

Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

Sagot :

miaumiau
[tex]V=Ed=0.20\times 6=1.20[/tex]
V=E d
d=.20 cm
E=6 V/cm
V=.20×6
  =1.2 V

Thanks for using our platform. We're always here to provide accurate and up-to-date answers to all your queries. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.