Answered

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Determine the potential difference between two charged parallel plates that are 0.20 cm apart and have an electric field strength of 6.0 V/cm.

Sagot :

miaumiau
[tex]V=Ed=0.20\times 6=1.20[/tex]
V=E d
d=.20 cm
E=6 V/cm
V=.20×6
  =1.2 V

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