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Calculate the de Broglie wavelength of an electron traveling at 3.0 × 107 m/s (me = 9.1 × 10-31 kg).

Sagot :

ParthKohli
Using the relation,

[tex]\lambda = \dfrac{h}{mv}[/tex]

We plug in the values in SI units.  Here, the values are:

[tex] h = 6.626 \times 10^{-34} J \cdot s[/tex]
[tex] m = 9.1 \times 10^{-31} kg[/tex]
[tex] v = 3.0 \times 10^{7} m/s[/tex]
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