Answered

Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Discover a wealth of knowledge from professionals across various disciplines on our user-friendly Q&A platform. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

Find dy/dx
2x+3y=sinx

Sagot :

[tex]2x+3y=sinx\\\\3y=sinx-2x\ \ \ \ /:3\\\\y=\frac{1}{3}(sinx-2x)\\\\\frac{\delta y}{\delta x}=\left[\frac{1}{3}(sinx-2x)\right]'=\frac{1}{3}\left[(sinx)'-(2x)'\right]=\frac{1}{3}(cosx-2)[/tex]
We appreciate your visit. Hopefully, the answers you found were beneficial. Don't hesitate to come back for more information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for using Westonci.ca. Come back for more in-depth answers to all your queries.