shornoramiller3
Answered

Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover reliable solutions to your questions from a wide network of experts on our comprehensive Q&A platform. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.

Write the quadratic equation whose roots are 2 and -6, and whose leading coefficient is 1 .(Use the letter  to represent the variable.)  =0

Sagot :

konrad509
[tex](x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12[/tex]
[tex]roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope this was helpful. Please come back whenever you need more information or answers to your queries. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.