shornoramiller3
Answered

Looking for answers? Westonci.ca is your go-to Q&A platform, offering quick, trustworthy responses from a community of experts. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Write the quadratic equation whose roots are 2 and -6, and whose leading coefficient is 1 .(Use the letter  to represent the variable.)  =0

Sagot :

konrad509
[tex](x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12[/tex]
[tex]roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0[/tex]
Visit us again for up-to-date and reliable answers. We're always ready to assist you with your informational needs. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.