shornoramiller3
Answered

Get the answers you need at Westonci.ca, where our expert community is dedicated to providing you with accurate information. Discover the answers you need from a community of experts ready to help you with their knowledge and experience in various fields. Get immediate and reliable solutions to your questions from a community of experienced professionals on our platform.

Write the quadratic equation whose roots are 2 and -6, and whose leading coefficient is 1 .(Use the letter  to represent the variable.)  =0

Sagot :

konrad509
[tex](x-2)(x+6)=\\ x^2+6x-2x-12=\\ x^2+4x-12[/tex]
[tex]roots\ are\ 2\ and\ -6\ and\ a=1\ then:\\\\1(x-2)(x+6)=0\\\\x\cdot x+x\cdot6-2\cdot x-2\cdot6=0\\\\x^2+6x-2x-12=0\\\\x^2+4x-12=0[/tex]
We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Discover more at Westonci.ca. Return for the latest expert answers and updates on various topics.