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Sagot :
x - $5 bills
y - $10 bills
x + y = 12
y = 5x
x + (5x) = 12
6x = 12
x = 2
y = 5(2)
y = 10
10 $10 bills and 2 $5 bills
y - $10 bills
x + y = 12
y = 5x
x + (5x) = 12
6x = 12
x = 2
y = 5(2)
y = 10
10 $10 bills and 2 $5 bills
Let $5 bills be denoted by x and $10 bills be denoted by y.
[tex]x + y = 12 \\ y = 5x \\ \\ x + (5x) = 12 \\ \\ 6x = 12 \\ \\ => x = 2 \\ \\ y = 5x \\ \\ or, y = 5(2) \\ \\ => y = 10[/tex]
Thus, there are 2 5$ bills and 10 10$ bills.
[tex]x + y = 12 \\ y = 5x \\ \\ x + (5x) = 12 \\ \\ 6x = 12 \\ \\ => x = 2 \\ \\ y = 5x \\ \\ or, y = 5(2) \\ \\ => y = 10[/tex]
Thus, there are 2 5$ bills and 10 10$ bills.
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