Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Our platform offers a seamless experience for finding reliable answers from a network of experienced professionals. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

Find the zeros of the function 
f(x)=x2+7x+12

Sagot :

When you factor, you get: (X+4)(x+3)
X=-3,-4
yungsherman

Answer:

-4,  -3

Step-by-step explanation:

So here we have a quadratic equation (meaning the highest exponent is 2).

[tex]f(x) = x^{2} +7x+12[/tex]

To solve a question like this we either factor or use the quadratic formula.  

Here we can factor.

To factor we must find two numbers that can be multiplied to make the last term, and summed to make the middle term.  In this equation it means we are finding two numbers such that:

___ * ___ = 12

and

___ + ___ = 7

We start by thinking of the factors of 12.

Lets start by trying 6 and 2.

6 * 2 = 12

but

6 + 2 = 8

So 6 and 2 dont work because they do not sum to 7.

Now lets try 4 and 3

4 * 3 = 12

and

4 + 3 = 7

This pair of numbers works because they can be multiplied to make 12 and added to make 7.

So we can write

[tex]f(x) = x^{2} +7x+12[/tex]

as

[tex]f(x) = (x+4)(x+3)[/tex]

Knowing this we can can find the zeros of the function.  Remember that a zero of a function is whatever can be plugged into x to make 0.  Since we know zero times any number equals 0, this equation will be 0 when x + 4 equals 0 or x + 3 equals 0.  

So we can solve for those two equations

x + 4 = 0

x = -4

x + 3 = 0

x = -3

So the two zeros of this equation are -4 and -3

We hope our answers were helpful. Return anytime for more information and answers to any other questions you may have. Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. We're glad you chose Westonci.ca. Revisit us for updated answers from our knowledgeable team.