Answered

Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Our platform provides a seamless experience for finding precise answers from a network of experienced professionals. Connect with a community of professionals ready to provide precise solutions to your questions quickly and accurately.

how do i solve 3x² - 8x + 2 = 0 using quadratic formula?

Sagot :

kayt91

[tex]x = \frac{-b +/- \sqrt{b^2 - 4ac}}{2a} [/tex]

[tex]x = \frac{-(-8) +/- \sqrt{(-8)^2 - 4(3)(2)}}{2(3)} [/tex]

[tex] x = \frac{8 +/- \sqrt{64 - 24}}{6} [/tex]

[tex]x = \frac{8 +/- \sqrt{40}}{6} [/tex]

[tex]x = \frac{8 +/- 6.31}{6} [/tex]

[tex]x = \frac{14.32}{6} [/tex]          x ≈ 2.39

[tex]x = \frac{1.68}{6} [/tex]            x ≈ 0.28

Lilith
[tex]3x^2 - 8x + 2 = 0\\ \\a=3 , \ \ b=-8 , \ \ c=2 \\ \\x_{1}=\frac{-b-\sqrt{b^2-4ac}}{2a} =\frac{8-\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} =\frac{8-\sqrt{ 64-24 }}{6} =\\ \\ =\frac{8-\sqrt{40 }}{6} = \frac{ 8-\sqrt{4\cdot 10 } }{6} = \frac{ 8-2\sqrt{ 10 }}{6} = \frac{2 (4-\sqrt{ 10 })}{6} = \frac{ 4-\sqrt{ 10 } }{3}[/tex]

[tex]x_{2}=\frac{-b+\sqrt{b^2-4ac}}{2a} =\frac{8+\sqrt{ (-8)^2-4 \cdot 3\cdot 2}}{2 \cdot 3} = \frac{ 4+\sqrt{ 10 } }{3}[/tex]



We appreciate your time on our site. Don't hesitate to return whenever you have more questions or need further clarification. We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Westonci.ca is here to provide the answers you seek. Return often for more expert solutions.