Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Join our Q&A platform to get precise answers from experts in diverse fields and enhance your understanding. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

how to solve it ...

1. 5-2x²-6x
2. (x+3) (x+4)=0


Sagot :

[tex]1.\\5-2x^2-6x=0\\-2x^2-6x+5=0\\\\a=-2;\ b=-6;\ c=5\\\\\Delta=b^2-4ac\to\Delta=(-6)^2-4\cdot(-2)\cdot5=36+40=76\\\\x_1=\frac{-b-\sqrt\Delta}{2a}\to x_1=\frac{6-\sqrt{78}}{2\cdot(-2)}=\frac{6-\sqrt{4\cdot19}}{-4}=\frac{6-2\sqrt{19}}{-4}=\frac{\sqrt{19}-3}{2}\\\\x_2=\frac{-b+\sqrt\Delta}{2a}\to x_2=\frac{3-\sqrt{19}}{2}[/tex]

=============================================================

[tex]2.\\(x+3)(x+4)=0\iff x+3=0\ \vee\ x+4=0\\\\x=-3\ \vee\ x=-4[/tex]
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. We hope this was helpful. Please come back whenever you need more information or answers to your queries. We're dedicated to helping you find the answers you need at Westonci.ca. Don't hesitate to return for more.