Answered

Discover the answers you need at Westonci.ca, a dynamic Q&A platform where knowledge is shared freely by a community of experts. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Explore comprehensive solutions to your questions from knowledgeable professionals across various fields on our platform.

expand and simplify: 
1.(n-2)(3n+7)+2n(2n+3)

factor each expression fully:
2. 4xsquared-25

Sagot :

Ananda26
1.(n-2)(3n+7)+2n(2n+3)
We'll start with (n-2)(3n+7)
Use the FOIL method to simplify: First, Outside, Inside, Last. 
Multiply the first numbers of each bracket (n and 3n), the outside numbers (n and 7), the inside numbers (-2 and 3n) and the last numbers (-2 and 7)
F=  3n×n= 3n²
O= n×7= 7n
I= -2×3n= -6n
L= -2×7= -14
Add them together, you get 3n² + n -14.
The second part is 2n(2n+3)
Multiply both numbers inside the bracket by 2n
2n×2n= 4n²
3×2n= 6n
Add these terms with the previous ones
7n² + 7n -14
Because they all have a common factor of 7, we can represent the equation as 
7(n² + n -2)

2. 4x²-25
To factor this, we convert it into two expressions that we multiply together (like converting -9 into 3×-3)
2x × 2x= 4x²
5 × -5= -25
The answer is (2x+5)(2x-5)
[tex]1.\\(n-2)(3n+7)+2n(2n+3)\\\\=n\cdot3n+n\cdot7-2\cdot3n-2\cdot7+2n\cdot2n+2n\cdot3\\\\=3n^2+7n-6n-14+4n^2+6n\\\\=7n^2+7n-14[/tex]

==============================================================

[tex]2.\\4x^2-25=(2x)^2-5^2=(2x-5)(2x+5)[/tex]
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Get the answers you need at Westonci.ca. Stay informed with our latest expert advice.