Answered

Welcome to Westonci.ca, your one-stop destination for finding answers to all your questions. Join our expert community now! Get detailed and accurate answers to your questions from a community of experts on our comprehensive Q&A platform. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields.

The vertex of the parabola y = x2 + 8x + 10 lies in Quadrant

Sagot :

kate200468
[tex]y = x^2 + 8x + 10\\\\The\ vertex=(p;\ q)\ \ \ and\ \ \ p=- \frac{b}{2a} ;\ \ \ q=- \frac{\Delta}{4a} ;\ \ \ \Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot10=64-40=24\\\\p=- \frac{8}{2\cdot1} =-4\\\\q=- \frac{24}{4\cdot1} =-6\\\\the\ vertex=(-4;-6)[/tex]
Lilith
[tex]y = x^2 + 8x + 10 \\ \\the \ standard \ form \ y = ax^2 + bx + c \\\\of \ a \ function \ into \ vertex \ form \ y = a(x - h)^2 + k ,\\ \\ we \ have \ to \ write \ the \ equation \ in \ the \ complete \ square \ form \\\\\ and \ vertex(h, k) \ is \ given \ by:[/tex]

[tex]h = \frac{-b}{2a} , \ \ k = c -\frac{b^2}{4a } \\ \\y = a(x - h)^2+k[/tex]

 opens  up for   a > 0

[tex] a=1 , \ \ b=8, \ \ c=10 \\ \\h= \frac{-8}{2}=-4[/tex]

[tex]k= 10-\frac{8^2}{4}=10-\frac{64}{4}=10-16=-6 \\ \\y=(x-(-4))^2+(-6)\\ \\y=(x+4)^2-6[/tex]
 


Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for visiting Westonci.ca. Stay informed by coming back for more detailed answers.