Answered

Discover answers to your questions with Westonci.ca, the leading Q&A platform that connects you with knowledgeable experts. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Experience the ease of finding precise answers to your questions from a knowledgeable community of experts.

The vertex of the parabola y = x2 + 8x + 10 lies in Quadrant

Sagot :

kate200468
[tex]y = x^2 + 8x + 10\\\\The\ vertex=(p;\ q)\ \ \ and\ \ \ p=- \frac{b}{2a} ;\ \ \ q=- \frac{\Delta}{4a} ;\ \ \ \Delta=b^2-4ac\\\\\Delta=8^2-4\cdot1\cdot10=64-40=24\\\\p=- \frac{8}{2\cdot1} =-4\\\\q=- \frac{24}{4\cdot1} =-6\\\\the\ vertex=(-4;-6)[/tex]
Lilith
[tex]y = x^2 + 8x + 10 \\ \\the \ standard \ form \ y = ax^2 + bx + c \\\\of \ a \ function \ into \ vertex \ form \ y = a(x - h)^2 + k ,\\ \\ we \ have \ to \ write \ the \ equation \ in \ the \ complete \ square \ form \\\\\ and \ vertex(h, k) \ is \ given \ by:[/tex]

[tex]h = \frac{-b}{2a} , \ \ k = c -\frac{b^2}{4a } \\ \\y = a(x - h)^2+k[/tex]

 opens  up for   a > 0

[tex] a=1 , \ \ b=8, \ \ c=10 \\ \\h= \frac{-8}{2}=-4[/tex]

[tex]k= 10-\frac{8^2}{4}=10-\frac{64}{4}=10-16=-6 \\ \\y=(x-(-4))^2+(-6)\\ \\y=(x+4)^2-6[/tex]
 


We hope our answers were useful. Return anytime for more information and answers to any other questions you have. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Thank you for choosing Westonci.ca as your information source. We look forward to your next visit.