Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Our platform provides a seamless experience for finding reliable answers from a network of experienced professionals. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.
Sagot :
from the formula of electric potential = (1/4πe)*(Qq/r), if one of the charge is doubled, the electric potential energy would be doubled too. Not so sure though, u might wanna double-check with someone else. But hope that helps. :)
Answer:
Magnitude of potential energy is increased by factor "2"
Explanation:
As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as
[tex]U = \frac{kq_1q_2}{r}[/tex]
now we know that if the charge of one of the charge particle is increased to twice of initial charge then
[tex]U' = \frac{kq_1(2q_2)}{r}[/tex]
now we can say from above two equations that
[tex]U' = 2U[/tex]
so on increase one of the charge to twice of initial value then the potential energy will become TWICE
We hope this information was helpful. Feel free to return anytime for more answers to your questions and concerns. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Keep exploring Westonci.ca for more insightful answers to your questions. We're here to help.