Discover the best answers at Westonci.ca, where experts share their insights and knowledge with you. Discover comprehensive answers to your questions from knowledgeable professionals on our user-friendly platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?

Sagot :

from the formula of electric potential = (1/4πe)*(Qq/r), if one of the charge is doubled, the electric potential energy would be doubled too. Not so sure though, u might wanna double-check with someone else. But hope that helps. :)

Answer:

Magnitude of potential energy is increased by factor "2"

Explanation:

As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as

[tex]U = \frac{kq_1q_2}{r}[/tex]

now we know that if the charge of one of the charge particle is increased to twice of initial charge then

[tex]U' = \frac{kq_1(2q_2)}{r}[/tex]

now we can say from above two equations that

[tex]U' = 2U[/tex]

so on increase one of the charge to twice of initial value then the potential energy will become TWICE

We hope you found what you were looking for. Feel free to revisit us for more answers and updated information. Thank you for your visit. We're committed to providing you with the best information available. Return anytime for more. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.