idestini2
Answered

Westonci.ca is the Q&A platform that connects you with experts who provide accurate and detailed answers. Get detailed and precise answers to your questions from a dedicated community of experts on our Q&A platform. Discover detailed answers to your questions from a wide network of experts on our comprehensive Q&A platform.

How does the electric potential energy between two charged particles change if one particle's charge is increased by a factor of 2?

Sagot :

from the formula of electric potential = (1/4πe)*(Qq/r), if one of the charge is doubled, the electric potential energy would be doubled too. Not so sure though, u might wanna double-check with someone else. But hope that helps. :)

Answer:

Magnitude of potential energy is increased by factor "2"

Explanation:

As we know that if two charge particles are placed at some distance "r" from each other then the electrostatic potential energy between two charge particles is given as

[tex]U = \frac{kq_1q_2}{r}[/tex]

now we know that if the charge of one of the charge particle is increased to twice of initial charge then

[tex]U' = \frac{kq_1(2q_2)}{r}[/tex]

now we can say from above two equations that

[tex]U' = 2U[/tex]

so on increase one of the charge to twice of initial value then the potential energy will become TWICE

Thank you for trusting us with your questions. We're here to help you find accurate answers quickly and efficiently. Thank you for choosing our platform. We're dedicated to providing the best answers for all your questions. Visit us again. Thank you for trusting Westonci.ca. Don't forget to revisit us for more accurate and insightful answers.