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4y-12x+8=0; Solve for y

Sagot :

iloveonedirection
[tex]4y-12x+8=0[/tex]

[tex]4y = 12x-8[/tex]

[tex]y = 3x - 2[/tex]
[tex]4y-12x+8=0\ \ \ \ /+12x\\\\4y+8=12x\ \ \ \ /-8\\\\4y=12x-8\ \ \ \ /:4\\\\y=\frac{12x}{4}-\frac{8}{4}\\\\y=3x-2[/tex]
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